PHP mysqli fetch_object() 函数
示例 - 面向对象的样式
返回结果集中的当前行，然后输出每个字段的值：
<?php
$mysqli = new mysqli("localhost","my_user","my_password","my_db");
if ($mysqli -> connect_errno) {
echo "Failed to connect to MySQL: " . $mysqli -> connect_error;
exit();
}
$sql = "SELECT Lastname, Age FROM Persons ORDER BY Lastname";
if ($result = $mysqli -> query($sql)) {
while ($obj = $result -> fetch_object()) {
printf("%s (%s)\n", $obj->Lastname, $obj->Age);
}
$result -> free_result();
}
$mysqli -> close();
?>
$mysqli = new mysqli("localhost","my_user","my_password","my_db");
if ($mysqli -> connect_errno) {
echo "Failed to connect to MySQL: " . $mysqli -> connect_error;
exit();
}
$sql = "SELECT Lastname, Age FROM Persons ORDER BY Lastname";
if ($result = $mysqli -> query($sql)) {
while ($obj = $result -> fetch_object()) {
printf("%s (%s)\n", $obj->Lastname, $obj->Age);
}
$result -> free_result();
}
$mysqli -> close();
?>
查看底部的程序样式示例。
定义和用法
fetch_object() / mysqli_fetch_object() 函数从结果集中取得当前行，并作为对象返回。
注释： 该函数返回的字段名是区分大小写的。
语法
面向对象的风格：
$mysqli_result -> fetch_object(classname, params)
程序风格：
mysqli_fetch_object(result, classname, params)
参数值
| 参数 | 描述 |
|---|---|
| result | 必需。规定由 mysqli_query()、mysqli_store_result() 或 mysqli_use_result() 返回的结果集标识符。 |
| classname | 可选。规定要实例化的类名称，设置属性并返回。 |
| params | 可选。规定一个传给 classname 对象构造器的参数数组。 |
技术细节
| 返回值: | 返回带有所取得行的字符串属性的对象。如果在结果集中没有更多的行则返回 NULL。 |
|---|---|
| PHP 版本: | 5+ |
| 更新日志: | 在 PHP 5.0.0 中新增了作为不同对象返回的功能。 |
示例 - 程序样式
返回结果集中的当前行，然后输出每个字段的值：
<?php
$con = mysqli_connect("localhost","my_user","my_password","my_db");
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
exit();
}
$sql = "SELECT Lastname, Age FROM Persons ORDER BY Lastname";
if ($result = mysqli_query($con, $sql)) {
while ($obj = mysqli_fetch_object($result)) {
printf("%s (%s)\n", $obj->Lastname, $obj->Age);
}
mysqli_free_result($result);
}
mysqli_close($con);
?>
$con = mysqli_connect("localhost","my_user","my_password","my_db");
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
exit();
}
$sql = "SELECT Lastname, Age FROM Persons ORDER BY Lastname";
if ($result = mysqli_query($con, $sql)) {
while ($obj = mysqli_fetch_object($result)) {
printf("%s (%s)\n", $obj->Lastname, $obj->Age);
}
mysqli_free_result($result);
}
mysqli_close($con);
?>
